Lesson 2.11 • Competency 2.7 & 2.8Complete Lesson
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Fluid Statics, U-Tubes & Hydrometry

Hydrostatic pressure (P = hρg), Pascal’s principle, Archimedes’ upthrust, law of flotation, U-tube manometers, Hare’s apparatus, and loaded test tube hydrometers.

Marking a lesson complete represents finishing your study of the topic; it does not denote tested mastery.

Learning Objectives

  • Calculate hydrostatic head pressure and understand the hydrostatic paradox.
  • Apply equilibrium conditions to U-tube immiscible manometers and Hare’s apparatus slope analysis.

Core Theory & Concepts

Fluid statics governs fluids at rest. The weight of fluid columns exerts pressure uniformly in all directions at a given depth. Immersed objects experience an upward buoyant upthrust equal to the weight of fluid displaced.

Hydrostatic Pressure & Datum Line

Pressure at depth h in liquid of density ρ is P = P₀ + hρg. In a U-tube, equal pressure across a horizontal plane through the lower interface gives h₁ ρ₁ = h₂ ρ₂.

P = P₀ + hρg, h₁ ρ₁ = h₂ ρ₂

Law of Flotation

A freely floating body displaces its own weight of fluid: M_body · g = (A · h) · ρ_liquid · g ⇒ M = (A · ρ) · h.

M = (A · ρ_L) · h

Common Misconceptions

Misconception

Believing pressure at the bottom of a container depends on the total volume or shape of the container.

Physical Clarification:Hydrostatic pressure depends solely on vertical liquid depth h, liquid density ρ, and gravity g (P = hρg). Container shape or total volume is completely irrelevant (the Hydrostatic Paradox).

Syllabus Topic Outline

Competency 2.7 & 2.8
  • 1Hydrostatic pressure P = h · ρ · g and atmospheric pressure P₀
  • 2Pascal’s Principle: hydraulic lift multiplication F₁/A₁ = F₂/A₂
  • 3Archimedes’ principle and upthrust U = V_disp · ρ_fluid · g
  • 4Law of flotation and hydrometer calibration

Practice Problems

1

In a U-tube, an oil column of height 20 cm is balanced by a 16 cm column of water. What is the relative density of the oil?